Question

A bounty hunting expedition located a very heavy sunken ship on the bottom of the sea. They are trying to raise it up with inflatable air balloons made of plastic. The plastic available is limited
Question - what is the FASTEST way to raise the treasure: 1000 balloons of volume 3 liters each or with 2 balloons of 1500 liters each ?
Solution:
This is a very basic example of very central method in physics - scaling of dimensions.
The Archimedes buoyant force upwards is proportional to volume of the bubble i.e. \[ R^3\] while the friction which slows the bubbles Down is proportional to their surface are which is proportional to \[ R^2 \] so the raftio \[ \frac{Buoyancy}{Viscosity} \,\,\sim R\] and it is better to use LArger bubbles. They rise faster

Answer 1

any arguments / reasons - of scientific type of course

Answer 2

Hmmm.
I'll think a little more.

Answer 3

Well, I take it back, If we consider the water's resisting viscous force the answer should be the case of two balloons and 1500 litres.

Answer 4

for the sake of clarity - explain a bit more extensive

Answer 5

Ah and bump-to-the-top the tricky question of yours that I solved

Answer 6

More the surface area of the object, More is the area provided for the retarding force offered by the liquid.


Yes. Well done, there.
There is one more approach to that. Although yours is simpler. :)
Will post the other method when I have time. Have to go now, thankyou for your question :)

Answer 7

Bump that question up

Answer 8

It is worth it (and the soln , I assume)

Answer 9

I cant. It says bump in 5380 minutes.

Answer 10

Well - I can

Answer 11

How

Answer 12

Oh well.Byee bye. :)

Answer 13

Bye and thanks for the \[ \color{#00FF00}{\Huge \cal{Gem \, \, \, of a \quad Question}} \]
http://openstudy.com/study#/updates/505e1877e4b02e1394101626

Answer 14

Solution:
This is a very basic example of very central method in physics - scaling of dimensions.
The Archimedes buoyant force upwards is proportional to volume of the bubble i.e. \[ R^3\] while the friction which slows the bubbles Down is proportional to their surface are which is proportional to \[ R^2 \] so the raftio \[ \frac{Buoyancy}{Viscosity} \sim R\] and it is better to use LArger bubbles. They rise faster