Question

Could somebody give me a hand with this question? What is the derivative of
y = sec θ tan θ

Answer 1

you can use the product rule, or you can use quotient rule after rewriting this as
\[y=\frac{\sin(x)}{\cos^2(x)}\]

Answer 2

probably easier to use
\[(fg)'=f'g+g'f\]
with \(f(x)=\sec(x), f'(x)=\sec(x)\tan(x), g(x)=\tan(x),g'(x)=\sec^2(x)\)

Answer 3

I tired using the product rule and got sec*sec^2+tan*sec*csc

Answer 4

I would assume that is not correct =).

Answer 5

there is no cosecant in it

Answer 6

derivative of secant is secant tangent, not secant cosecant
that is your only mistake

Answer 7

If I rewrote the question in terms of division, wouldn't I have to use the chain rule?