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F(x) = sqrt(x^2+2x) x>0 Find the inverse of the function.
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Swap x and F(x) then solve for F(x)
I tried that but I didn't know where to go from there, I ended up with x = sqrt(y^2+2y) then x^2 = y^2 +2y, then x^2-y^2 = 2y and now I am at (x+y)(x-y) = 2y, I dont know where to go from here
to get y by itself
complete the square... y^2 + 2y + ?
y^2 +2y +1 = (y+1)^2
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Where did the 1 come from though?
so if we add 1 to both sides we get... x^2 +1 = y^2 +2y +1 x^2 +1 = (y+1)^2
oh okay, let me see if I can figure it out from here
k
Thanks a lot I figured it out! :)
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great!
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