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The x-intercept of 3x + 2y = 12 is (__, 0). so im trying to find x right????
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put y=0 3x=12 x= 12/3=4
3(12)+2y=12??
3(4)+2*(0)=12
oh ok but why is x 4?
put y=0 you will get 3x= 12 now divide both sides by 3 \[\frac{ 3x }{ 3 }=\frac{ 12 }{ 3 }=4=x\]
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alright thanks! :)
so the answer to The y-intercept for 3x + 2y = 12 is (0,___). would be 6
yep (:
thanks :)
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