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OpenStudy (anonymous):
How many atoms of phosphorus are in 2.30 mol of copper(II) phosphate? I'm having trouble figuring out the steps. I do know Avogadro's number is needed! 6.022x10^23
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OpenStudy (btaylor):
First: Write the Equation --> Cu2PO4 In 1 mol of Cu2PO4, there is 1 mol of P. So in 2.30 mol of Cu2PO4, there is 2.30 mol of P. So: 2.30 x 6.022x10^23 = atoms of P
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