Question

factor: x³-2x²+2x-1

Answer 1

use synthetic division.

Answer 2

i cant ? there's nothing to divide by

Answer 3

-b+/- the square root of b^2 - 2ac/ all over 2(a)
i think the one you can add and put to the right of the equal sign let me try

Answer 4

this is what I got:
i took out an x:
x(x^2 - 2x + 1) = 1
+2 +/- squ.root -2^2 - 2(1)(2) / 2(1)

2+/- squ root -4-4 / 2

2+/- squ root -8 /2, the ans can be either a pos: 2+squ root -8 / 2 or neg:2-squroot -8 /2

Answer 5

x³-2x²+2x-1= (x-1)(x^2-x+1)

since x^2-x+1 has no real solution use the quadratic formula

Answer 6

@lilsis76 i dont think we can do that cause this isnt an equation

Answer 7

hmm...okay i thought that would work.

Answer 8

Use trial and error first of all.

Answer 9

x³-2x²+2x-1

Inserting 1 in x, makes the equation zero.

Answer 10

Hence,

x=1
x - 1 =0

Therefore, (x-1) is a factor..

Now divide.

Answer 11

x^2-x+1

Answer 12

(x-1)(x^2 - x + 1)

Bingo!

now factor the quadratic too!

Answer 13

oh so this is the factor theorem right ?

Answer 14

Sure it is.