An object is dropped from a 32 m building and strikes the ground with a speed of 31m/s . How tall is the building ?
what is the acceleration?
Gravity should equal 9.8
ok so i recommend you write down what is given, look at the 3 formulas and play around with what is given and what you need
the math in physics is basic, its the process that requires a bit of thinking
\[mgh = \frac{1}{2}mv^2\]
Eightforlunch can you please explain the equation is I never used it before and I don't know what it means ?
jk_16 what equation do you think I should use . Can you please break it down in steps if you can ?
@chelster your question asks for the height of the building. It says in the problem that the building is 32 m tall. Then, isn't the height of the building intuitively obvious?
32m
mass*gravity*height=1/2*mass*final velocity squared. This is the conservation of energy. In other words, potential energy mgh, in joules, is equal to kinetic energy, 1/2mv^2, also in joules. Plug in the numbers you have, and holy crap, I just realized @BTaylor has a point. I don't think we're working with the original problem here...
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