Question

Find the derivative

f(t) = sqrt(t^2 +1), a = 3

Answer 1

\[f'(t) = \frac{ 2t }{ 2\sqrt{t ^{2}+1} }\]

Answer 2

had you understood how it become?

Answer 3

I understand how you got 2t on the top, but on the bottom can you explain your steps? My algebra is apparently rusty, I didn't get that.

Answer 4

it is like (2t^2 + 1)^1/2
when we diffrentiate number its power come in front and its power is become after subtracting 1
for example- derivative of x^3 is 3x^(3-1)

Answer 5

Ohh I see you used the fast methods, my professor is making us use the definition derivatives

Answer 6

So I multiplied it by \[\sqrt{(t+h)^2+1} + \sqrt{t^2 + 1} / \sqrt{(t+h)^2+1} + \sqrt{t^2 + 1}\] to remove the square root from the top, I see that after canceling a "h" I can get 2t on the top, but my math is wrong on the bottom and am not seeing how i can get what your got.

Answer 7

i dont know about your method