Question

See below thank you in advance.

Answer 1

Clearly F & G are out...need a little more help

Answer 2

25pi

Answer 3

with justification/explanation please :-)

Answer 4

H i think...
Make a diagnol which will pass through the centre of the circle and apply pythagoras ...
Hyp^2 = 8^2+ 6^2
Hyp = 10

Radius will be 5in.
Area of circle = pi*r^2
Area = 25pi

Answer 5

perfect say no more thank yoU!!!

Answer 6

Using pythagoras theorem x can be found.
\(x^2=6^2+8^2\)
\( =36+64\)
\( =100\)
\(x=10\)
And x is the diameter of the circle
r=x/2
=10/2
area of the circle=\(\pi*r^2\)