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Mathematics
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(cotx - 1)(squareroot of 3 cotx + 1) = 0
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so either \(\cot(x)=1\iff \sin(x)=\cos(x)\) or \[\cot(x)=-\frac{1}{\sqrt{3}}\iff \tan(x)=\sqrt{3}\] and your job is to solve for \(x\) now it should be somewhat easier
tnx
yw
whoa except i made a mistake last line should read \[\tan(x)=-\sqrt{3}\] i dropped the minus sign by mistake
tnx again
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which makes \(x=\frac{2\pi}{3},\frac{5\pi}{3},...\) i hope you have an interval over which to solve
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