Question

Which is true for the graph of
y=x^2-9 over
x^2-4
answers: vertical asymptotes at x = ±3
horizontal asymptotes at y = ±2
vertical asymptotes at x = ±2
horizontal asymptote at y = 0

Answer 1

A vertical asymptote is going to occur here where the denominator is 0, since division by 0 is not defined.

A horizontal asymptote where the degree of the numerator is the same as the degree of the denominator is simply the ratio of the constants (-9 and -4).

Answer 2

thanks

Answer 3

oh what vetucak asymptote there is 2 in the answer

Answer 4

set x^2 - 4 = 0 and solve for x. That is where the vertical asymptotes will be.

Answer 5

so c is correct

Answer 6

Yes

Answer 7

k man thanks