Question

Solve the equation.

Answer 1

\[x+\sqrt{5x+19}=-1\]

Answer 2

the book says -3
how do they get that

Answer 3

\(\large x+1=-\sqrt{5x+19}\)
now square both sides

Answer 4

so \[x ^{2}-5x+20=0 \] and then factor

Answer 5

thats incorrect, how did u get that ?

Answer 6

squaring both sides \[x ^{2}+1=5x+19\]

Answer 7

\(\huge(x+1)^2 = x^2 +2x+1\)

Answer 8

ok how did you get the x^2+2x+1

Answer 9

\(\huge (a+b)^2 = a^2+2ab+b^2\)

Answer 10

\[x ^{2}+2x+1=5x+19\]

Answer 11

yup, shift 5x+19 on left

Answer 12

so then \[x ^{2}-3x+20\]

Answer 13

1-19=-18

Answer 14

this is what I have \[x ^{2}+2x+1-5x+19=0\]

Answer 15

nopes, u had to subtract 19

Answer 16

\(x ^{2}+2x+1-5x-19=0\)

Answer 17

ok so I have x=6 and x=-3

Answer 18

u got it.

Answer 19

the book has it as the answer just being x=-3

Answer 20

ok, put x= 6 in original equation, see whether it gets satisfied.

Answer 21

so then you probably have to put them back in to see if they both are equal

Answer 22

yup

Answer 23

u won't get equal for x=6

Answer 24

ok awesome I have a couple more problems to solve

Answer 25

sorry, i got to go :(
post it as a new question, many are there to help u.....