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Mathematics 13 Online
OpenStudy (anonymous):

simplify the expression: 4-y^2/y^2+3y+2

OpenStudy (radar):

Factor the numerator and denominator getting;\[(2 + y)(2-y) \over (y+2)(y+1)\]proceed from there.

OpenStudy (anonymous):

so that gives you y-2/y+1 right?

OpenStudy (radar):

more like (2-y)/(y+1) or (y-2)/(-y-1) or \[- (y-2) \over (y+1)\]

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