How can the polynomial 6d^4 + 9d^3 - 12d^2 be factored?
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OpenStudy (anonymous):
Do you see something in common with each term that can be factored out first
OpenStudy (icalibear):
they're all divisible by 3?
OpenStudy (anonymous):
and d^2
OpenStudy (icalibear):
okay so what do I do next :s
OpenStudy (anonymous):
2d^2+3d-4
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OpenStudy (anonymous):
now we factor the polynomial
OpenStudy (icalibear):
3d^2(2d^2 + 3d - 4)?
OpenStudy (anonymous):
(2d + ___)(d - ____) or (2d - ____)(d + ____)
OpenStudy (anonymous):
correct
OpenStudy (icalibear):
oh okay
thanks
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OpenStudy (anonymous):
lets factor the poly now
OpenStudy (icalibear):
ok so
OpenStudy (anonymous):
look at the last term first. what are the numbers when multiplied get -4.
OpenStudy (anonymous):
1,-4 -1,4 2,-2 -2,2
OpenStudy (icalibear):
yea
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OpenStudy (anonymous):
now we look at the center terms coefficient and we need to find the pair of numbers when added equal 3. but we can't forget about the 2 the will alos be multiplied to one of the numbers also.
OpenStudy (anonymous):
its a little bit of guess and check
OpenStudy (icalibear):
so we combine them? and get 6d
OpenStudy (icalibear):
so the answer to this would be 3d^2(3d^2 + 6d -9)??
OpenStudy (anonymous):
i don't know how you got there and I also can't factor the poly. so i would leave the answer as what you typed half way up
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