Question

How to solve -(3-a)^2+4(5-a)?

Answer 1

mostly the 1st part

Answer 2

What are you trying to solve here?
Is this the entire problem?

Answer 3

If this is an equation, you need to have an equal sign somewhere.

Answer 4

I don't get how to do the part when theres an exponent outside the equation of 2

Answer 5

Just to simplyfy

Answer 6

Oh, you need to use the formula (a+b)^2 = a^2 + 2ab + b^2. Replace the values you have and see if you can get the result.

Answer 7

I don't understand what that is? Isn't the 2 just put into the 3 which is 9 and a^2

Answer 8

why 2ab?

Answer 9

Because you need to account for what is inside the parentheses. Here is an example:

(2+3)^2 = 2^2 + 2*2*3 + 3^2 = 4 + 12 + 9 = 25

We know that 2+3=5, therefore 5^2 = 25;

Now do this with your numbers. And take care with the minus sign.

Answer 10

I get the part with 2^2 and 3^2 but i didnt know you had to add them inside and square them too

Answer 11

So what would you simplifie the equation at the top

Answer 12

Your correct result would be -(3-a)^2 = -(3^2 - 2*3*a + a^2) = -9 + 6a - a^2

Answer 13

k ty