Question

find four consecutive even integers such that -4 times the sum of the first and the fourth is six greater than the opposite of the sum of the second and the fourth

Answer 1

Let the consecutive even integers be x, x+2, x+4, x+6

Answer 2

ok ik how to get that far... its the solving i dont understand

Answer 3

-4(x+x+6)=6[-(x+2+x+6)

Answer 4

so it would be -4x+-4x+-24=6x+12+6x+36 right??

Answer 5

to avoid problems solve, inside brackets first, so left hand side would be -4(2x+6) which is -8x-24

Answer 6

ok

Answer 7

Solve for x, and then plug in and find other integers, got it?

Answer 8

uhmm i think so not sure

Answer 9

So far you did good, except on the right hand side, you left out the negative sign

Answer 10

oh wait where does the negative sign go then???

Answer 11

So far you have
-8x-24=-12x-48

Answer 12

ok so add -8x to -12x and add -48 to -24 right??

Answer 13

i got x=-6

Answer 14

Yes, you ended up with the right answer, be able to show your work in your home work. Punch -6 into the four integers all the way at the top that we started with.

Answer 15

so x=-6 -6+2 -6+4 and -6+6

Answer 16

oh btw thank yhu(: