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Solve the equation.
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\[2\sqrt{x}+8-8=-2-8\] \[2\sqrt{x}=-10\] now what wold you do?
i did that... and then i found the square root x and got 2x= -10
no you have to do something with the 2? so what do you think?
i have no idea :/
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\[2\sqrt{x}=-10\] so since I'm multipling by 2 the I need to divide by 2 to move it to the other side \[\sqrt{x}=-10/2\] \[\sqrt{x}=-5\] then square both sides \[\left( \sqrt{x} \right)^{2}=\left( -5 \right)^{2}\] \[x=25\]
did this help
this helped so much!!! thank you!
but wouldn't it be -25?
no because negative times negative is postive
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