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A 118.63 g sample of SrCl2·6H2O was heated and 34.81 grams of water were recovered from the sample. What percent of the original H2O remains in the sample following this heating?
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Find % of water by mass for the sample Find % of water in your sample after boiling Subtract to find the answer (remains)
so i first do 34.81 x 1mol H2O/ mw H2O x 100
nvm thats for after.
i dont know how to set a problem to find the 1st part..
You take the mass of the water in the original formula divided by the total molecular mass So mass of (6 H2O)/(Sr Cl2 6 H2O)
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Did you get how to do this?
I don't really get what the question is saying
@e.mccormick
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