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Mathematics 13 Online
OpenStudy (anonymous):

Prove: if a|b and a>0, then (a,b)=a

OpenStudy (anonymous):

(a,b) stands for gcd(a,b), correct? What is the definition you're given of gcd? I just want to make sure it matches the one I'm using.

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

gcd(a,b) means d|a and d|b

OpenStudy (tamtoan):

if a divide b (a|b) , a is a multiple of b, so you can write a = cb (c time b) where c is a constant., from there you can conclude that gcd(a,b) = a

OpenStudy (tamtoan):

in this case your d = cb = a

OpenStudy (anonymous):

instead of a = cb.. shouldn't it be b = ac since a|b?

OpenStudy (anonymous):

how about the fact that a>0?

OpenStudy (tamtoan):

i am not familiar with the notation a|b ...read a divide b...if a is larger then a = cb, if b is larger then b = ca ..., one of those is right...because i learned maths from a country different than the US

OpenStudy (anonymous):

a divides b means b is the larger one.. so b = ac

OpenStudy (tamtoan):

ok so b = ac , so gcd(a,b) = gcd(a,ac) = a , right? , i don't know why is the condition a > 0, for me, i would think condition is a not equal to zero since a is in the denominator, it can't be zero...

OpenStudy (anonymous):

yeah you're right..

OpenStudy (anonymous):

thank you so much

OpenStudy (tamtoan):

np, enjoy :)

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