let g(x)= 1+x-[x] and f(x)= -1,x1 then for all x f[g(x)] is equal to a)x b)1 c)f(x) g(x)

Question

let g(x)= 1+x-[x] and f(x)= -1,x<0
                                           0, x=0
                                           1, x>1
then for all x f[g(x)] is equal to
a)x  b)1  c)f(x)  g(x)

tamtoan · Answer

what is [x] ? is it absolute value of x ? if yes, then answer is b

anonymous · Answer

[x] is the integer fn ( dont knw greatest or smallest integer fn)
and the ans is b
how did u do dat

anonymous · Answer

[x] is to mean that ' the greatest integer of x'.

anonymous · Answer

can anyone explain me greatest/smallest integer fn

anonymous · Answer

so how do u solve for those type functions

tamtoan · Answer

thanks zekarias

tamtoan · Answer

[x] is greatest integer of x , does it mean if  0 <= x <= 1 then [x] is 1 ? and   -3 <= x <= -2 then [x] is -2 ?

hartnn · Answer

no, the other way round

hartnn · Answer

[1.5] =1
[-1.5]=-2

hartnn · Answer

also called floor function

hartnn · Answer

defination :For all real numbers x, the greatest integer function returns the largest integer less than or equal to x.

anonymous · Answer

Here is the answer...
For values of x the expression x-[x] is b/n 0 and 1 so that 1+x-[x] is always above 1.
Therefore f([g(x)]) = f(>1)=1
Thus answer B

anonymous · Answer

thanks all