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Mathematics 22 Online
OpenStudy (anonymous):

|x + 3| < 5

OpenStudy (anonymous):

x=2

OpenStudy (anonymous):

i mean x=1....it has to be less than two

OpenStudy (anonymous):

algebra

OpenStudy (anonymous):

and it should turn out to be one of these –8 < x < 2 –2 < x < 8 3 < x < 5 –3 < x < 5

OpenStudy (anonymous):

Algebraically, you know that you have an absolute value inequality. It is already isolated on one side. That means you can split the inequality into two cases. x + 3 < 5 OR x + 3 > -5. Then you solve each algebraically to get x < 2 or x > -8.

OpenStudy (anonymous):

-3<x<-5

OpenStudy (anonymous):

It's the first option, if you look at what I wrote, the first option is the way to restate it.

OpenStudy (anonymous):

ok what about this |–3n| – 2 = 4 ------------- 2 or –2 3 or –3 4 or –4 6 or –6

OpenStudy (anonymous):

So you have an absolute value equation. Your first goal is to isolate everything in the absolute value bars on one side of the equation. Here, that is accomplished by adding two to both sides. The equation becomes the absolute value of -3n = 6.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

Next, you split the equation into two cases. Either -3n = 6, or -3n = -6, because of the absolute value. (Absolute value is distance from zero, so that distance could be going either direction on a number line).

OpenStudy (anonymous):

Then you solve both cases separately. In case one, divide both sides by -3 to isolate n. There n = -2. In case two, divide both sides by -3 to isolate n. There n = 2. So, n = 2 or -2.

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