Question

A bicycle is turned upside down while its owner repairs a flat tire on the rear wheel. A friend spins the front wheel, of radius R, and observes that drops of water fly off tangentially.She measures the height reached by drops moving vertically (see figure below). A drop that breaks loose from the tire on one turn rises verticall 54 cm above the tangent point.A drop that breaks loose on the next turn rises 51 cm above the tangent point. The radius of the wheel is 0.381m. a.) why does the first drop rise higher than the second drop?b.)Neglecting air friction and using only the observed heights and the radius of the wheel, find the wheel's angular acceleration(assuming it to be constant)

Answer 1

Are u sure it is Angular a that you want and not Radial a ?

Answer 2

the wheel's omega has changed.
find the water drop's Vi from Vi^2 = 2gh
find omega for each drop from omega = V/r
delta omega is alpha
remember to do everything in meters, meters/sec, etc.

Answer 3

yes, its the angular