What is the equation of the line in standard form that passes through the point (3, –2) and is parallel to the line y = –4x + 1?

x + 4y = 10

x – 4y = –10

4x – y = –10

4x + y = 10

Question

What is the equation of the line in standard form that passes through the point (3, –2) and is parallel to the line y = –4x + 1? 

x + 4y = 10

x – 4y = –10

4x – y = –10

4x + y = 10

ajprincess · Answer

The gradients of parallel lines are equal.
So the gradient of the required line =-4.
$y-y_1=m(x-x_1)$
$y-(-2)=-4(x-3)$
Can u do nw?

mathlegend · Answer

Also remember that when looking for a line that is parallel you are looking for the slope to be the same. So in the equation...

y=mx+b

m is the slope so it must be -4x

mathlegend · Answer

Just follow @ajprincess steps

ajprincess · Answer

Guess it is a typo. m=-4 and nt -4x. @MathLegend