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Mathematics 21 Online
OpenStudy (anonymous):

help!!

OpenStudy (anonymous):

\[\left( \sqrt{3}+i \right)\left( \sqrt{3}-2i \right)\]

OpenStudy (anonymous):

i have an idea how to solve, just not too sure if im right

OpenStudy (jwheele1):

there are a few ways...

OpenStudy (jwheele1):

im sure you are most familiar with FOIL...right?

OpenStudy (anonymous):

yeah

OpenStudy (jwheele1):

|dw:1348707296753:dw|

OpenStudy (jwheele1):

|dw:1348707305046:dw|

OpenStudy (jwheele1):

step one. multiply together...and you get what

OpenStudy (jwheele1):

wait....do you mean \[\sqrt{3}\]

OpenStudy (anonymous):

square root of 3

OpenStudy (jwheele1):

ok cool

OpenStudy (jwheele1):

alright so what is that times itself

OpenStudy (anonymous):

square root of 9...?

OpenStudy (jwheele1):

yes which is what

OpenStudy (anonymous):

3

OpenStudy (jwheele1):

1*1 = 1 2*2 = 4 . . . ?*? = 9

OpenStudy (jwheele1):

oh ...ys lol

OpenStudy (jwheele1):

so when ever you multiply a square root by its clone you remember that its the number underneath the root

OpenStudy (jwheele1):

|dw:1348707542618:dw|

OpenStudy (jwheele1):

sq rt of 3 * -2i

OpenStudy (anonymous):

wouldnt it be \[2i \sqrt{3}\]

OpenStudy (anonymous):

**-2i

OpenStudy (jwheele1):

yes

OpenStudy (jwheele1):

|dw:1348707732324:dw|

OpenStudy (jwheele1):

|dw:1348707764376:dw|

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