A lighthouse is located on a small island 3km away from the nearest point P on a straight shoreline and its light makes 4 revolutions per minute. How fast is the beam of light moving along the shoreline when it is 1 km from P?
.6 km per minute
hello @TranceNova
\[\tan \theta=y/x\]
\[\sec^2\theta(\frac{ d \theta }{ dt }=\frac{ xdy }{ dt }-\frac{ ydx }{ dt } /(x^2)\]
the right side is all over x^2
\[\frac{ dy }{ dt }=\frac{ x^2(\sec^2\theta)\frac{ d \theta }{ dt } +y\frac{ dx }{ dt }}{ x }\]
yep yep
\[\frac{ 3^2(\frac{ 1 }{ \cos^2\theta })(8\pi)+1(0) }{ 3 }\]
|dw:1348714601605:dw|
@TranceNova my question to you is, whats the answer for 1/cos^2o?
my book says the answer is 8pi/3 km/min but isnt cos^2theta (3/root10)^2?
@bahrom7893 hey
so im pretty much at the end, and I want to now what i am messing up :) thanks for listening
Wait I'm kinda lost.. let me reread the problem.
im getting 80pi/3
so it is 10 right?
http://answers.yahoo.com/question/index?qid=20110308160630AAZ3vZc This answer summarizes it nicely
ok good, thank you so much @bahrom7893 !
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