you can just about do it in your head with a little practice
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OpenStudy (anonymous):
I won't bother simplifying that.
OpenStudy (anonymous):
thanks 4 making fun of me satellite 73 :p
OpenStudy (anonymous):
you know i am only funnin
OpenStudy (anonymous):
Funning haha...
OpenStudy (anonymous):
you got this or no?
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OpenStudy (anonymous):
lololohaha but no seriously i dont understand it:{
OpenStudy (anonymous):
ok lets do this one
\[\ln(\sin(x))\] in your head you can write \[\frac{\cos(x)}{\sin(x)}\]
OpenStudy (anonymous):
the derivative of sine is cosine, that goes up top, sine goes in the bottom
OpenStudy (anonymous):
\[\ln(x^2+2x)\] derivative is
\[\frac{2x+2}{x^2+2x}\] just like that
OpenStudy (anonymous):
derivative of inside piece up top, inside piece itself down below
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OpenStudy (anonymous):
okay but no......wait! ur confusing the beJesus outta me :IIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIII
OpenStudy (anonymous):
ok i will shut up and wait
OpenStudy (anonymous):
no dont shut up........shut up while taking it too fats maybe going slower? explaining each step?
OpenStudy (anonymous):
fast i mean UGH!
OpenStudy (anonymous):
you are asked for the derivative of the log of something right? i mean something other than just \(x\)
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OpenStudy (anonymous):
ok?
OpenStudy (anonymous):
so i will say you are asked for the derivative of \(\ln(f(x))\) i.e. the log of some other function of \(x\)
OpenStudy (anonymous):
so far so good?
OpenStudy (anonymous):
ehhhhhhhhhhhh i guess :I
OpenStudy (anonymous):
like for example
\(\ln(1+e^x)\)
or \(\ln(\sin(x)\)
or \(\ln(x^2+2x)\)
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OpenStudy (anonymous):
in other words the log of something
\(\ln(\text{something})\)
OpenStudy (anonymous):
we good so far?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
check your work on: wolframalpha.com
OpenStudy (anonymous):
ok so this is how you do it:
make a fraction
take the derivative of the inside piece, put it up top
put the inside piece itself in the denominator
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OpenStudy (anonymous):
okay
OpenStudy (anonymous):
that is all
OpenStudy (anonymous):
so how about
\[\ln(\sin(x))\]?
OpenStudy (anonymous):
its ln(cosx/sinx)
OpenStudy (anonymous):
it would be without the log
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OpenStudy (anonymous):
o.
OpenStudy (anonymous):
y?
OpenStudy (anonymous):
i can explain if you like, lets get a correct answer first
OpenStudy (anonymous):
k
OpenStudy (anonymous):
so?
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OpenStudy (anonymous):
um. do i do the sma e4 my prob right??
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
same
OpenStudy (anonymous):
for my problem?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
after you simplify as suggested
that is after you write
\[\ln(1+e^x)-\ln(1-e^x)\]
OpenStudy (anonymous):
will i have e^x/1+e^x?
OpenStudy (anonymous):
for the first term, yes
OpenStudy (anonymous):
okay and i am supposed 2 do this as well to the second term?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
satellite 73?
OpenStudy (anonymous):
o okay and then do i do the quotient rule for both or wat?
OpenStudy (anonymous):
no then you are done
OpenStudy (anonymous):
what?! really?!
OpenStudy (anonymous):
you don't take the derivative twice! not unless you want the second derivative
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OpenStudy (anonymous):
i think you are confused as to what we are doing
we are not simplifying the expression, we are finding the derivative
OpenStudy (anonymous):
o okay thanks i think that is all for today thanks for helping me i really appreciate it...i dont have my brother to help me since he went back to school and its been pretty tough having that i am sucky at math THANK YOU!
OpenStudy (anonymous):
yw, hope it is clear, and also hope it is clear that it is easy to do!
derivative of \(\ln(\sin(x))\) is \(\frac{\cos(x)}{\sin(x)}\)
derivative of \(\ln(x^2+2x)\) is \(\frac{2x+2}{x^2+2x}\)
derivative of \(\ln(1+e^x)\) is \(\frac{e^x}{1+e^x}\)