Question

[Calculus] derivative using the quotient rule
y=5/cosx

Answer 1

well you can write your equation as

\[y = 5 \sec(x) \]

or perhaps

\[y = 5(\cos(x))^{-1} \]

and apply the cain rule...

Answer 2

oops chain rule

Answer 3

\[\prime =\frac{ 5sinx }{ \cos ^{2}x}\]

Answer 4

is it right? :)

Answer 5

No. Just use the quotient rule.

Answer 6

Im pretty sure thats what they want you to do since it tells you to solve it that way.

Answer 7

Derivative of Trig func. using quotient rule.

Answer 8

y'=5/cosx
= {[(cosx-sinx)(cosx)]-[(sinx+cosx)(-sinx)]}/cos^2x
= (cos^2x-sinxcosx)-(-sin^2x-sinxcosx)/cos^2x
=(cos^2x-sinxcosx+sin^2x+sinxcosx/cos^2x
=cos^2x+sin^2x/cos^2x

Answer 9

Thanks!

Answer 10

Thank you! :)