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differentiate 2x^3+10/9x
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6x^2+10/9
\[\huge (2x)^3 + \frac {10} { 9x } \\ \huge => 8x^3 + \frac { 10} {9x} \]
@Rohangrr I believe it's 2(x^3) not the entire quantity cubed. But I could be wrong.
it should be 6x^2 but I cant get the last part right
It should just be 10/9
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would it be 90x^-1/2
I tired and it said the answer was not correct
2^3 = 2*2*2 = 8 Hence @Rohangrr is correct
Its a differentiate problem so the power would drop one and be multiplied to the base
@MathTHEORY It is 2(x^3) not (2x)^3 And when deriving (10/9)x=10/9
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So the differentiation is: \[6x^{2}-\frac{ 10 }{ 9x^{2} }\]
I tried that earlier, it didnt work
@marlrich The differentiation of 10/9x is: |dw:1348727606677:dw|
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