Find the volume for the regular pyramid.
the volume of regular pyramid is 1/3 * base area * height can u find the height ?
i tried and then everything was wrong..
ok, so lets take simpler thing first, area of base. since its a regular pyramid, the base is an equilateral triangle. Area of equilateral triangle ?
4 root 3?
its 3/4 * side^2 = (3/4) *4*4 = ?
root 3 over 4...
1/3 X area-of-base X perpendicular height = Volume of pyramid
@angelicapad
put x=4
formula for an equilateral triangle is s^2 * root3/4
ok sorry, so root 3 /4 *4*4 = 4 root 3, thats correct, i m sorry.
yaa
so whats the problem
now , we just need to find height.
so 4 root 3 represents what exactly?
the problem is just that every number i come up with, comes up wrong
the slant height(s) is also 4 here, so we can use the formula to get the height(h) \(s^2 = h^2 + a^2/12\) 4 root 3 is just the area of base we need to multiply by height and 1/3 to get the volume.
what is a?
a is the length of base , also = 4 here
a little confused on the formula
wait i found one more easier formula here : http://www.mathsisfun.com/geometry/triangular-pyramid.html
base area + 0.5 * perimeter * side length
perimeter?
nevermind, that was for surface area.
oh
i have a different problem if you want to help me with that instead?
i wish the height was given here, it makes the solution very simple... and yes, whats the other problem ?
lateral area
that is a hexagonal pyramid
yeah
ok, height is given then its easy u can find slant height using, pythagoras theorem
\(\sqrt{8^2+6^2}\)
10
ok, we need to find apothem of pyramid...u know how to ?
i suck at that -.-
ok, here's the formula : slant ht.^2 = apothem^2 +(base side/2)^2<----pythagoras theorem so 10^2=Ap^2+3^2
Ap = \(\sqrt{91}\)
ahhh, i got that right!
now lateral surface area = Ap * perimeter of base /2
perimeter of base = 6* sides = 6*6 = 36
lateral area = 36/2 * \(\sqrt{91}\) = 18 \(\sqrt{91}\) =
171.7
thats all i had to put, it said it was right :) 18 root 91 thank you! again haha
ok, welcome... trying 1st problem ? volume
no its fine :) after i got the last one right it said i was done because i got over 90%
congrats !
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