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Mathematics 18 Online
OpenStudy (anonymous):

Find the volume for the regular pyramid.

OpenStudy (anonymous):

hartnn (hartnn):

the volume of regular pyramid is 1/3 * base area * height can u find the height ?

OpenStudy (anonymous):

i tried and then everything was wrong..

hartnn (hartnn):

ok, so lets take simpler thing first, area of base. since its a regular pyramid, the base is an equilateral triangle. Area of equilateral triangle ?

OpenStudy (anonymous):

4 root 3?

hartnn (hartnn):

its 3/4 * side^2 = (3/4) *4*4 = ?

OpenStudy (anonymous):

root 3 over 4...

OpenStudy (mayankdevnani):

1/3 X area-of-base X perpendicular height = Volume of pyramid

OpenStudy (mayankdevnani):

@angelicapad

OpenStudy (mayankdevnani):

put x=4

OpenStudy (anonymous):

formula for an equilateral triangle is s^2 * root3/4

hartnn (hartnn):

ok sorry, so root 3 /4 *4*4 = 4 root 3, thats correct, i m sorry.

OpenStudy (mayankdevnani):

yaa

OpenStudy (mayankdevnani):

so whats the problem

hartnn (hartnn):

now , we just need to find height.

OpenStudy (anonymous):

so 4 root 3 represents what exactly?

OpenStudy (anonymous):

the problem is just that every number i come up with, comes up wrong

hartnn (hartnn):

the slant height(s) is also 4 here, so we can use the formula to get the height(h) \(s^2 = h^2 + a^2/12\) 4 root 3 is just the area of base we need to multiply by height and 1/3 to get the volume.

OpenStudy (anonymous):

what is a?

hartnn (hartnn):

a is the length of base , also = 4 here

OpenStudy (anonymous):

a little confused on the formula

hartnn (hartnn):

i got it from this source : http://mathworld.wolfram.com/TriangularPyramid.html

hartnn (hartnn):

wait i found one more easier formula here : http://www.mathsisfun.com/geometry/triangular-pyramid.html

hartnn (hartnn):

base area + 0.5 * perimeter * side length

OpenStudy (anonymous):

perimeter?

hartnn (hartnn):

nevermind, that was for surface area.

OpenStudy (anonymous):

oh

OpenStudy (anonymous):

i have a different problem if you want to help me with that instead?

hartnn (hartnn):

i wish the height was given here, it makes the solution very simple... and yes, whats the other problem ?

OpenStudy (anonymous):

lateral area

hartnn (hartnn):

that is a hexagonal pyramid

OpenStudy (anonymous):

yeah

hartnn (hartnn):

ok, height is given then its easy u can find slant height using, pythagoras theorem

hartnn (hartnn):

\(\sqrt{8^2+6^2}\)

OpenStudy (anonymous):

10

hartnn (hartnn):

ok, we need to find apothem of pyramid...u know how to ?

OpenStudy (anonymous):

i suck at that -.-

hartnn (hartnn):

ok, here's the formula : slant ht.^2 = apothem^2 +(base side/2)^2<----pythagoras theorem so 10^2=Ap^2+3^2

hartnn (hartnn):

Ap = \(\sqrt{91}\)

OpenStudy (anonymous):

ahhh, i got that right!

hartnn (hartnn):

now lateral surface area = Ap * perimeter of base /2

hartnn (hartnn):

perimeter of base = 6* sides = 6*6 = 36

hartnn (hartnn):

lateral area = 36/2 * \(\sqrt{91}\) = 18 \(\sqrt{91}\) =

hartnn (hartnn):

171.7

OpenStudy (anonymous):

thats all i had to put, it said it was right :) 18 root 91 thank you! again haha

hartnn (hartnn):

ok, welcome... trying 1st problem ? volume

OpenStudy (anonymous):

no its fine :) after i got the last one right it said i was done because i got over 90%

hartnn (hartnn):

congrats !

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