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solve the radical equations: √3x + 10 = 2+√x+2
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Is this your question? \(\sqrt{3}x+10=2+\sqrt{1}x+2\)
@glares25 ?
yes
you have square roots so you should square both sides then move all constants onto one side and all unknowns on the other side then work from there
Take the radicals at one side & constants at one side & then square both sides & then solve :)
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are u sure its not this \(\sqrt{3x+10}=2+\sqrt{x+2}\) and its actually what jitesh wrote ?
@hartnn yes that one
then u directly square both sides, what u get ?
wait
ok, thank you so much .. i can work on my own ,thanks :)
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sure? coz we haven't even started yet....
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