Compute the angle A if B= 81° 50' and C= 94°30' in a spherical triangle whose side c= 90°
spherical triangle....heard for 1st time... sum of angles = 180 degrees, holds for this ?
180<(A+B+C)<540°
cool question :) Is this a triangle overlaid on a sphere? Like connecting New York, Dallas, and Seattle? I don't know if "sum of angles = 180" holds...
yeah. thats spherical trigonometry called sphaerica developed Menelaus' theorem.
sum of three vertex angles of a spherical triangle is greater than 180° and less than 540° 180<(A+B+C)<540°
u know law of sines for this ?
u can use that sin a/sin A = sin b/sin B = sin c/sin C
oh, wait, 2 sides and one angle given, maybe law of cosines will help cos A = - cos B.cos C + sin B.sin C.cos a
no side a given. how? :D
so u need cos a..hmm
there's no side b&c given to get cos a
i can think of this, .... find sin a in terms of sin A from sin law find cos a in terms of cosA from cos law, then square and add to eliminate 'a'
is that confusing ?
yeah.
just find sin a in terms of sinA from sin law...and tell me what u get
i dont get it. v.v
could u? i m getting sin a =1.0031 sin A
sin a/ sin A = sin 90 / sin 94.5
ah..okay
so u get sin a =1.0031 sin A now from cos law can u find cos a in terms of cos A ?
yup.
what u get ?
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