a statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 49.0 and 59.0 minutes. Find the probability that a given class period runs between 50.5 and 51.25 minutes.
@Ottomaticc here is a question that i have. it says graph and find area of shaded region but I dont know what the vertical graph would be
the book gives an example and it says .5 so you subtract 50.5 from 51.25 and get .75, and then you multiply it by the vertical height to get the shaded area but it's not the right answer.
it says .075 it the answer. and i divide .75 from .075 and get .1 but IDK where they get .1 from.
total length of time is ten minutes from 50.5 to 51.25 is .75 minutes the proportion of the time is \(\frac{.75}{10}=.075\)
yep what satellite said, just remembered as he put it up^
in other words it is the length of the favorable time divided by the total length. that is all height is silly because uniform means height is fixed, so ignore it
pick a point \(x\) at random on the interval \([0,2]\) what is the probability \(.9<x<1.2\) ? it is \(\frac{.3}{2}\) that is all
oh okay i understand. because in the book, it doesn't divide. it multiplies lol and it doesnt used total length. thanks guys
i am sure it does in some way you have to divide to get the probability
ooohhhhh i get it.
easy right?
for now.. lets see if the rest of the problems are just as simple!
haha the problems always get harder
Thank you @satellite73 this helps alot! started Stats 2 today, stats is my worst xD
yeah , good luck as judge judy always says "the questions get harder"
yw
hey lets all study together on here lol
I can't this minute, I'm busy going over C3 math, but fan me, I will do stats with you next time :P
roger that!
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