how to factor 36x^2y^6 - 16

Question

ajprincess · Answer

$36x^2y^6 - 16$
$=6^2x^2(y^3)^2-4^2$
$=(6xy^3)^2-4^2$
Difference of squares.
$a^2-b^2=(a-b)(a+b)$
Here $a=6xy^3$ and $b=4$
Is it clear?

anonymous · Answer

Good explanation :)  Hope tkennedy is reading it :)

ajprincess · Answer

thnx a lot for the compliment @JakeV8

anonymous · Answer

yes thank you!

anonymous · Answer

now can you help me with 9x^4y^2 - z^6

anonymous · Answer

@tkennedy   using the "difference of squares" idea that you just saw eloquently explained, can you make this next problem into a difference of squares format?  May need to play with the exponents...

ajprincess · Answer

$36x^2y^6-16$
$=4(9x^2(y^3)^2-4)$
$=4(3^2x^2(y^3)^2-2^2)$
$=4((3xy^3)^2-2^2$
Difference of squares
$a^2-b^2=(a-b)(a+b)$
here $a=3xy^3$ and $b=2$

anonymous · Answer

yes thank you. Now  1 - 100x2

ajprincess · Answer

I remember helping u to solve this earlier. Am I right?

anonymous · Answer

i don't remember

anonymous · Answer

how about a^2b^2 - d^2

ajprincess · Answer

Can u plz take a look at this http://openstudy.com/users/tkennedy#/updates/5061e8f9e4b0583d5cd2de00

ajprincess · Answer

What problem do u hav in "difference of squares" questions?