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Mathematics 13 Online
OpenStudy (anonymous):

P(-d

OpenStudy (kropot72):

Divide 0.5408 by 2. Then use the resulting value of probability to find the value of z from the standardised normal distribution table. z = d.

OpenStudy (anonymous):

divide 0.5408 by 2 check the number on both positive and negative z table 0.5408/2 =0.2704

OpenStudy (anonymous):

by the way tables they are not all same but they have different techniques to find the same answer

OpenStudy (anonymous):

thank you!!!

OpenStudy (anonymous):

u r welcom

OpenStudy (anonymous):

I have another question! could you guys help? @REMAINDER @kropot72

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

a county has been experiencing a mean of 35.3 motor vehicle deaths each year. whats the probability of more than two motor vehicle deaths on any given day

OpenStudy (anonymous):

btw I am not getting the right answer with dividing by two with the previous question

OpenStudy (anonymous):

wat do u get

OpenStudy (anonymous):

okay so is p(-d<z<d) = .5408 and divide by two thats .2704 and i looked on the chart and it gives me -.61 but the answer is .74 so how do they get that

OpenStudy (anonymous):

did 'nt they gave u a standad deviation ?for the second question

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

this is what it says.

OpenStudy (anonymous):

OpenStudy (anonymous):

the standard distribution = \[\sqrt{mean}\]

OpenStudy (anonymous):

the formula is given. P(x) = \[\frac{ mean ^{x} \times e^{-mean} }{ x! }\]

OpenStudy (anonymous):

and if it asks for more than 2, then that would be P(a) = 1-complement of p(a) so 1- [p(0) +p(1)+p(2)] but the answer isnt right.

OpenStudy (anonymous):

oh this is poisson

OpenStudy (anonymous):

yes lol myyyyy bad

OpenStudy (anonymous):

this was a question from last chapter.

OpenStudy (anonymous):

i also don't get their answer ok @zarkon even if he is offline but he will find lets hope he will solve it because most of my stats question have been answered by him.

OpenStudy (anonymous):

ok thanks

OpenStudy (anonymous):

lets try that one of d again

OpenStudy (anonymous):

okay so theres two different problems. a. if P(-d<z<d) = .5408, find d b. if P(-e<z<e) = .2586, find e

OpenStudy (anonymous):

yes the first one is o.74 check this |dw:1348775161188:dw|\ and on the table 0.7704 is 0.74

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