Question

give a substitution (not necessarily a trigonometric) which could be used to find the integral of x/sqrt{(x^2+10}

Answer 1

try \(u=x^2+10\) and you will be done quickly

Answer 2

,did you get what satellite is saying?

Answer 3

yes thank you!

Answer 4

integral of x/sqrt{(x^2+10}
let u=(x^2+10)
du=2xdx sub this
integral of x/sqrt{(x^2+10}
=(1/2)integral of 2xdx/sqrt{(x^2+10}
=(1/2)integral of2u^(-1/2) du
=(1/2)u^1/2 /(1/2)
=sqrt(x^2+10) +C