Question

Solve each system of equations by using substitution:
The Algebra 2 Math Book says #17 is a no solution. How is it show your work and steps on how it's not a solution.

17. 6x - 3y = 12
2x = 8 - y

Answer 1

So first you would have to get one of the variables by itself. Since the second equation has a single 'y' why not use that one?

Answer 2

We can add y to both sides then subtract 2x from both sides leaving us with...
y=-2x+8

Answer 3

So now we can substitute y into the first equation.

Answer 4

6x-3(-2x+8)=12

Answer 5

6x+6x-24=12

Answer 6

12x-24=12

Answer 7

12x=36

Answer 8

x=3

Answer 9

wait

Answer 10

What don't you understand?

Answer 11

I am trying to get caught up

Answer 12

oh ok

Answer 13

???

Answer 14

2x = 8 - y
+y +y
----------
y+2x=8
-2x -2x
---------
y=-2x+8

(Got it?)

Answer 15

ready for next step

Answer 16

Okay

Answer 17

So now that we solved for x... we can substitute it into the 1st equation.

Answer 18

6(3) - 3y = 12

Answer 19

18 - 3y=12
-18 -18
-----------
-3y= -6
--------
y=2

Answer 20

the book says it's not a solution

Answer 21

Yes it is a solution. So I do not know why your book says no. My guess would be a typo.

Answer 22

okay

Answer 23

I also just plugged it into an equation checker and it shows it as a solution

Answer 24

okay help me on my other problem, the people there are poop