Find the slope of the tangent to the curve xy^2+x^2y=2 at the point (1,1)

(implicit differentiation by the way)

I got -3 but my friend got -5

Question

Find the slope of the tangent to the curve xy^2+x^2y=2 at the point (1,1) 

(implicit differentiation by the way)

I got -3 but my friend got -5

anonymous · Answer

Hi... :)

anonymous · Answer

tangent to the curve means a line with the same slope as the curve, right?

anonymous · Answer

(oh wait... help me recall implicit differentiation...  sorry, thought I knew this better)

anonymous · Answer

differentiate with respect to x the whole term

anonymous · Answer

y^2+2xy(dy/dx)+2xy+x^2(dy/dx)=0

anonymous · Answer

now put in the values and you will get it

anonymous · Answer

do i move the dy/dx's to one side though before putting values?

anonymous · Answer

@apoorwa

anonymous · Answer

@JakeV8

anonymous · Answer

yes
thats wat you have to do move dy/dx on one side that will give you the slope. remember to take sign of dy/dx to be positive

anonymous · Answer

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