Question

Find the slope of the tangent to the curve xy^2+x^2y=2 at the point (1,1)

(implicit differentiation by the way)

I got -3 but my friend got -5

Answer 1

Hi... :)

Answer 2

tangent to the curve means a line with the same slope as the curve, right?

Answer 3

(oh wait... help me recall implicit differentiation... sorry, thought I knew this better)

Answer 4

differentiate with respect to x the whole term

Answer 5

y^2+2xy(dy/dx)+2xy+x^2(dy/dx)=0

Answer 6

now put in the values and you will get it

Answer 7

do i move the dy/dx's to one side though before putting values?

Answer 8

@apoorwa

Answer 9

@JakeV8

Answer 10

yes
thats wat you have to do move dy/dx on one side that will give you the slope. remember to take sign of dy/dx to be positive