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Mathematics 13 Online
OpenStudy (perl):

In a college population of 10,000 people, suppose you want to randomly pick a sample of 1000 for a survey. For any particular sample of 1000, if you are sampling with replacement, what is the chance of picking the first person .  what is the chance of picking a different second person . and lastly, what is  the chance of picking the same person again. please help me, i think i can do the first one.

OpenStudy (anonymous):

"what is the chance of picking the first person" doesn't really make sense, unless the idea is with a population of 10,000, on the first selection, what are the chances of picking any particular person? In that case, it would just be 1/10,000

OpenStudy (perl):

it does make sense, wikipedia has an answer, but dont cheat

OpenStudy (perl):

and no, the answer should be .1

OpenStudy (anonymous):

well, I think wikipedia should be trusted implicitly. Why do you question it? Submit to Wikipedia and enjoy crowd-sourced peace.

OpenStudy (perl):

here is the link of wikipedia http://en.wikipedia.org/wiki/Simple_random_sample

OpenStudy (perl):

well it also agrees with my book

OpenStudy (perl):

scroll down to the example

OpenStudy (perl):

here is my book excerpt

OpenStudy (perl):

, in a college population of 10,000 people, suppose you want to randomly pick a sample of 1000 for a survey. For any particular sample of 1000, if you are sampling with replacement, the chance of picking the first person is 1000 out of 10,000 (0.1000); the chance of picking a different second person for this sample is 999 out of 10,000 (0.0999); the chance of picking the same person again is 1 out of 10,000 (very low). If you are sampling without replacement, the chance of picking the first person for any particular sample is 1000 out of 10,000 (0.1000); the chance of picking a different second person is 999 out of 9,999 (0.0999); you do not replace the first person before picking the next person. Compare the fractions 999/10,000 and 999/9,999. For accuracy, carry the decimal answers to 4 place decimals. To 4 decimal places, these numbers are equivalent (0.0999).

OpenStudy (perl):

i dont really understand the chance of picking a different second person

OpenStudy (perl):

i agree that these questions are not very clear

OpenStudy (perl):

here is wikipedia's wording Let us assume you had a school with 1000 students, divided equally into boys and girls, and you wanted to select 100 of them for further study. You might put all their names in a bucket and then pull 100 names out. Not only does each person have an equal chance of being selected, we can also easily calculate the probability of a given person being chosen, since we know the sample size (n) and the population (N): 1. In the case that any given person can only be selected once ie. after selection person is removed from the selection pool (basic probability):

OpenStudy (anonymous):

sleep beckons, sorry for my attitude... you're doing good work here, and I honestly applaud it... helping, generously, is the best. and omg, that was quite a complete solution just now... extremely well done!

OpenStudy (perl):

heh, well that was copy and paste. thanks for trying :)

OpenStudy (perl):

i think , whats the probability of a person being selected *given* 100 people were selected

OpenStudy (perl):

well ill keep working on it , cya

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