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show that 3cos^2-sin^2=1+2cos2x
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use, cos2x = cos^2x-sin^2x
Solving right hand side first @hartnn
yup, easier
I will go with Left then..
let asker try first
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i did use that rule but i got stuck there
which step exactly? can u show your work?
so that we can guide u from there
put cos^2(x)= 1/2 (1+cos2x) and sin^2(x)= 1/2 (1 - cos2x) to get the reqd ans
Show your work first @david warner..
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i basically did it from the LHS .. used the cos(2x) rule .. so i hhad 3(cos2x) and then (3(2cos^2x-1)
thats where u did the mistake....its 3cos^2-sin^2 and not 3cos^2-3sin^2.... write cos^2(x)= 1/2 (1+cos2x) and sin^2(x)= 1/2 (1 - cos2x)
ohh i see it now .. thanku :)
welcome ^_^ ask if there are still doubts anywhere
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