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evaluate f(g(0)) and g(f(1)) where f(x)=sgrt(x^2-1) and g(x)=(x^2+1)/(x^2-1)
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i think i got f(g(x)) to be sqrt((x^2+1)/(x^2-1)-1) and g(f(x)) to be sqrt(((x^2+1)/(x^2-1))^2-1)
not required.. can u find g(0) =?
well i think g(0) would be -1
yup, thats correct, now find f(-1)
which if you plug -1 into f(x) would be 0?
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yup, so f(g(0)) = 0 got this?
so g(f(1)) would be -1?
yup
awesome thanks!
welcome ^_^
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by chance want to help with another problem?
by every chance.....
2^(1+cosx)=4
i think the next step is log(base 2)1+cosx=log(base 2)4
write 4 as 2^2
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no need to take log 2^(1+cos x) = 2^2 so 1+cos x =2 got this?
soo cosx=1?
yup
i think im thinking too hard ha. thanks!
welcome :)
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