Question

Solve.

(5x/7)+(3y/7)=1
x+(2y/3)=1

I keep getting fractions and I know that is not the right answer.

Answer 1

is it dividing or is it fractions?

Answer 2

factions

Answer 3

\[(5x\div7)+(3y\div7)1\] or is \[(\frac{5x}{7})+(\frac{3y}{7})=1\]

Answer 4

use substitution by rewriting the 2nd equation as

x = 1 - 2y/3

and substitute into equation 1

\[\frac{5(1 - \frac{2y}{3}}{7} +\frac{3y}{7} = 1\]

multiply each term by 7 as the 1st step

Answer 5

\[\frac{ 5x }{ 7 }+\frac{ 3y }{ 7 }=1\]
\[x+\frac{ 2y }{ 3 }=1\]