A lot is in the shape of a trapezoid. The sum of the bases is 280 feet. If the area of the lot is 8,400 square feet, what is the distance across the lot, i.e. the altitude of the figure? The altitude of the trapezoid is______feet.
The formula for the area of a trapezoid A is: \[A=(\frac{b1+b2}{2})\times h\]So the altitude h is: \[h=A \times (\frac{2}{b1+b2})=8400\times \frac{2}{280}=?feet\]
where did you get 2 i thought its 1/2
When rearranging the formula for area to find the altitude in terms of area and base lengths the following term must be inverted \[(\frac{b1+b2}{2})\] to give \[(\frac{2}{b1+b2})\]
ok
so H is not important than???
60
h is what we need to find. As I wrote previously \[h=\frac{8400\times 2}{280}\] which you correctly calculated asas 60 feet.
*as
if we looking for area what formula do i use??
The area of what?
the last problem that i worked on we were looking for area trapezoid right
we were looking for H im sorry
The formula for area that you messaged me is basically the same as the one that I have posted here. They are different ways of expressing the same. So you can use either for area. Either formula for area can be rearranged to find h if the area and bases are known>
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