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Mathematics 10 Online
OpenStudy (anonymous):

how to solve 1-|2x+5|< or equal to 13

OpenStudy (anonymous):

What do you think you should do first?

OpenStudy (anonymous):

im not sure if i should multiply the whole thing by a negative to cancel it out or just divide by one and then distribute the negative

OpenStudy (anonymous):

Well the 1 isnt being multiplied so i would just start by subtracting it from both sides

OpenStudy (anonymous):

and then do you just distribute the negative and solve it

OpenStudy (anonymous):

You wouldnt distribute the negative, thats just absolute value not parentheses. The absolute value of -2x+5 is just 2x+5. So then you solve \[2x+5\le12\]

OpenStudy (anonymous):

thanks dude i got confused on the first part

OpenStudy (anonymous):

Thats alright. You got \[x \le7/2\] right?

OpenStudy (anonymous):

yep and im graphing it now

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