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Given that for any positive integer n, the sum, S(n), of the first n positive integers can be evaluated using the formula S(n) = n(n+1)/2, what is the sum of all integers,n, such that 50
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hint : sum of all integers,n, such that 50<n<100 =sum of first 99 positive integers-sum of first 50 positive integers
why it is the sum of the 50, but not 51?
u have a formula for that in ur question S(n) = n(n+1)/2
because your n starts from 51 so u need to subtract 1st 50 terms and not 51
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