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Mathematics 8 Online
OpenStudy (anonymous):

Factor by grouping 25b^3+105b^2-100b

OpenStudy (anonymous):

common out b here b(25b^2 + 105b + 100)

OpenStudy (campbell_st):

take 5b as a common factor leaving \[5b(5b^2 + 21b - 20)\] now factorise the quadratic.

OpenStudy (lopus):

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