Question

suppose f(2)=-4, g(2)=2, f'(2)=-5, g'(2)=3. Find h'(2) where h(x)=4f(x)-2g(x)

Answer 1

isn't it h'(x) = 4f'(x) - 2g'(x) ?

Answer 2

no you have to find h'(2) given the equation 4f(x)-2g(x)

Answer 3

well, after you have h'(x) ...just substitute when x = 2, h'(2) = ?

Answer 4

ok thanks

Answer 5

np

Answer 6

Integrate f' to f is -5x + c and you know f(2) = -4 = -5(2) + c etc etc.