Question

2sec^2(x)+tan^2(x)-3=0.....lost

Answer 1

There is a substitution for sec^2 of x that we should know here.

Answer 2

\(sec^2x=1+tan^2x\)

Answer 3

Can u solve it nw @jotwestmoreland?

Answer 4

Substitute (\1+tan^2x\) in place of \(sec^2x\) and try solving. can u do @jotwestmoreland?

Answer 5

@ajprincess i get stuck at 2+2tan^2x+tan^2x-3=0

Answer 6

\[2+2tan^2x+tan^2x-3=0\]
\[3tan^2x-1=0\]
\[3tan^2x=1\]
\[tan^2x=\frac{1}{3}\]
\[tanx=\frac{1}{\sqrt3}\]
\[x=tan^{-1}(\frac{1}{\sqrt3})\]
\[x=30^o\]
Is it clear @jotwestmoreland?