Solve the systems using substitution.

6x + 2y = 0
4x + y = -1

Question

Solve the systems using substitution.

6x + 2y = 0
4x + y = -1

anonymous · Answer

here's one substitution you can do:

in the second equation, let y=-4x-1.
substitute this into the first equation:  6x + 2(-4x-1) = 0

can you take it from here?

anonymous · Answer

No :/ Please show me step by step

anonymous · Answer

No :/ Please show me step by step

anonymous · Answer

6x + 2(-4x-1) = 0

carry out distributive property on the multiplication with the parenthesis:
6x + 2(-4x-1) = 0
6x + (2*-4x) - (2*-1) = 0
6x + (-8x) - (-2) = 0

how 'bout now?.... can you do the rest?

anonymous · Answer

6x + 2 (-4x + 1) = 0
6x – 8x + 2 = 0
-2 + 2 = 0

anonymous · Answer

?

anonymous · Answer

Whoops I thought it was a positive 1 I didnt see the negative

anonymous · Answer

6x + (-8x) - (-2) = 0
6x - 8x + 2 = 0
-2x + 2 = 0

how 'bout from here then....

anonymous · Answer

X = -1

anonymous · Answer

is that right?