Question

Solve the systems using substitution.

6x + 2y = 0
4x + y = -1

Answer 1

here's one substitution you can do:

in the second equation, let y=-4x-1.
substitute this into the first equation: 6x + 2(-4x-1) = 0

can you take it from here?

Answer 2

No :/ Please show me step by step

Answer 3

No :/ Please show me step by step

Answer 4

6x + 2(-4x-1) = 0

carry out distributive property on the multiplication with the parenthesis:
6x + 2(-4x-1) = 0
6x + (2*-4x) - (2*-1) = 0
6x + (-8x) - (-2) = 0

how 'bout now?.... can you do the rest?

Answer 5

6x + 2 (-4x + 1) = 0
6x – 8x + 2 = 0
-2 + 2 = 0

Answer 6

?

Answer 7

Whoops I thought it was a positive 1 I didnt see the negative

Answer 8

6x + (-8x) - (-2) = 0
6x - 8x + 2 = 0
-2x + 2 = 0

how 'bout from here then....

Answer 9

X = -1

Answer 10

is that right?