Question

I HAVE my digital circuits xam tommorow.. cnany1 plz help me out wid this problem

Find the complement of the expression:
(A'B + CD)E' + E

Answer 1

no help :(

Answer 2

Simply use D Morgan Theorem
(A+B')(C'+D')E'

Answer 3

I think it will be:-
(A'B+CD)E'+E
USING DEMORGAN
>>[(A'B+CD)E'+E]'
>>[(A'B+CD)'+E"".E'] i.e E"=E
>>{[(A"+B')(C'+D')]+0} i.e E.E'=0
>>(A+B')(C'+D')

Answer 4

get the dual of the expression and then compliment each of the variable , that is the shot cut to check ur result
dual expression : (A'+B)(C+D)+EE'
when each variable is complimented :
((A')' + B' ) (C' +D')+1'= (A+B')(C'+D')+0= (A+B')(C'+D')