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OpenStudy (anonymous):
solve the equation using the square root property. I need to understand how to break it down to get the answer. -5(x-6)2-15=-30 the 2 is square
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OpenStudy (phi):
use ^ to show a power:
-5(x-6)^2-15=-30
OpenStudy (phi):
do you know you could add 15 to both sides of the equation, right?
\[ -5(x-6)^2-15+15=-30+15\]
can you simplify this?
OpenStudy (anonymous):
then divide 5 to both sides?
OpenStudy (phi):
divide by -5
OpenStudy (anonymous):
now I have (x-6) = 3
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OpenStudy (anonymous):
add 6 to each side
OpenStudy (phi):
what happened to the ^2 ?
OpenStudy (phi):
it should be
(x-6)^2 = 3
OpenStudy (phi):
now you can do the square root on both sides
OpenStudy (anonymous):
x=9
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OpenStudy (phi):
no.
-5(x-6)^2-15=-30
becomes
(x-6)^2 = 3
you must take the square root of both sides
OpenStudy (anonymous):
x=3 or x= -3
OpenStudy (anonymous):
are you still there?
OpenStudy (phi):
do you know how to take the square root of
(x-6)^2
?
OpenStudy (anonymous):
I thought I did, but can you show me please?
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OpenStudy (anonymous):
is it x=2 or x-2
OpenStudy (phi):
\[ \sqrt{ x^2} = x\]
\[ \sqrt{ (x+2)^2} = x+2\]
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